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缘由：
在工作中碰到了这么一个问题，记录一下解决方案及其过程，方便以后参考。
正文：
参考解答：
先给出结论：
- 要替换的字符数量不多时，可以直接链式replace()方法进行替换，效率非常高；
- 如果要替换的字符数量较多，则推荐在 for 循环中调用 replace() 进行替换。
可行的方法：
1. 链式replace()
string.replace().replace()
1.x 在for循环中调用replace()「在要替换的字符较多时」
2. 使用string.maketrans
3. 先 re.compile 然后 re.sub
……
def a(text): chars = "&#" for c in chars: text = text.replace(c, "\\" + c)def b(text): for ch in ['&','#']: if ch in text: text = text.replace(ch,"\\"+ch)import redef c(text): rx = re.compile('([&#])') text = rx.sub(r'\\\1', text)RX = re.compile('([&#])')def d(text): text = RX.sub(r'\\\1', text)def mk_esc(esc_chars): return lambda s: ''.join(['\\' + c if c in esc_chars else c for c in s])esc = mk_esc('&#')def e(text): esc(text)def f(text): text = text.replace('&', '\&').replace('#', '\#')def g(text): replacements = {"&": "\&", "#": "\#"} text = "".join([replacements.get(c, c) for c in text])def h(text): text = text.replace('&', r'\&') text = text.replace('#', r'\#')def i(text): text = text.replace('&', r'\&').replace('#', r'\#') |
参考链接：
- http://stackoverflow.com/questions/3411771/multiple-character-replace-with-python
- http://stackoverflow.com/questions/6116978/python-replace-multiple-strings
- =
- http://stackoverflow.com/questions/8687018/python-string-replace-two-things-at-once
- http://stackoverflow.com/questions/28775049/most-efficient-way-to-replace-multiple-characters-in-a-string
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《 “Python中如何快速进行多个字符的替换” 》 有 2 条评论
Python string中删除(过滤)掉emoji表情字符
http://blog.csdn.net/orangleliu/article/details/67632628
http://stackoverflow.com/questions/33404752/removing-emojis-from-a-string-in-python
http://stackoverflow.com/questions/10992921/how-to-remove-emoji-code-using-javascript
比正则快 M 倍以上！Python 替换字符串的新姿势！
https://mp.weixin.qq.com/s/BcH541fFpnK6V0H5jZTlag
https://github.com/vi3k6i5/flashtext
`
This module can be used to replace keywords in sentences or extract keywords from sentences. It is based on the FlashText algorithm.
`
https://arxiv.org/abs/1711.00046